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| rev | Admin | (Created page with "'''Answer: A''' <math>E(Y)=\bar{a}_{10}+e^{-\delta(10)} e^{-\mu(10)} \bar{a}_{x+10}</math> <math>=\frac{\left(1-e^{-0.6}\right)}{0.06}+e^{-0.7} \frac{1}{0.07}</math> <math>=14.6139</math> <math>Y > E(Y) \Rightarrow\left(\frac{1-e^{-0.06 T}}{0.06}\right)>14.6139</math> <math>\Rightarrow T >34.90</math> <math>\operatorname{Pr}[Y > E(Y)]=\operatorname{Pr}(T>34.90)=e^{-34.90(0.01)}=0.705</math> {{soacopyright|2024}}") | Jan 18'24 at 23:12 | +422 |