Exercise


Jan 18'24

Answer

Answer: A

[math]E(Y)=\bar{a}_{10}+e^{-\delta(10)} e^{-\mu(10)} \bar{a}_{x+10}[/math]

[math]=\frac{\left(1-e^{-0.6}\right)}{0.06}+e^{-0.7} \frac{1}{0.07}[/math]

[math]=14.6139[/math]

[math]Y \gt E(Y) \Rightarrow\left(\frac{1-e^{-0.06 T}}{0.06}\right)\gt14.6139[/math]

[math]\Rightarrow T \gt34.90[/math]

[math]\operatorname{Pr}[Y \gt E(Y)]=\operatorname{Pr}(T\gt34.90)=e^{-34.90(0.01)}=0.705[/math]

Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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