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| rev | Admin | (Created page with "'''Solution: C''' There are <math>2 n</math> half years at coupon rate .045 per half year and yield rate .04 per half year. <math>1100 v^{2 n}=190</math> so <math>v^{2 n}=190 / 1100</math>. <math display="block"> P=C v^{2 n}+1000(.045) a_{\overline{2 n} \mid .04}=190+45 \frac{1-v^{2 n}}{.04}=190+45 * \frac{1-190 / 1100}{.04}=1120.682 </math> '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web...") | Nov 29'23 at 16:59 | +590 |