Exercise


Nov 29'23

Answer

Solution: C

There are [math]2 n[/math] half years at coupon rate .045 per half year and yield rate .04 per half year. [math]1100 v^{2 n}=190[/math] so [math]v^{2 n}=190 / 1100[/math].

[[math]] P=C v^{2 n}+1000(.045) a_{\overline{2 n} \mid .04}=190+45 \frac{1-v^{2 n}}{.04}=190+45 * \frac{1-190 / 1100}{.04}=1120.682 [[/math]]

References

Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.

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