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| rev | Admin | (Created page with "'''Solution: B''' <math display="block"> \begin{gathered} \text { January } \quad \text { July } \\ K(1.05)^{22}+K(1.1025)(1.05)^{21} \\ +K(1.1025)(1.05)^{20}+K(1.1025)^2(1.05)^{19} \\ +\ldots+\ldots \\ +K(1.1025)^9(1.05)^2+K(1.1025)^{10}(1.05)^1 \\ =11 K(1.1025)^{11}+11 K(1.1025)^{11}(1.05) \\ =65.96463 K=11000 \end{gathered} </math> Thus <math>K=11000 / 65.96463=166.7560</math>.") | Nov 26'23 at 22:11 | +388 |