Exercise


Nov 26'23

Answer

Solution: B

[[math]] \begin{gathered} \text { January } \quad \text { July } \\ K(1.05)^{22}+K(1.1025)(1.05)^{21} \\ +K(1.1025)(1.05)^{20}+K(1.1025)^2(1.05)^{19} \\ +\ldots+\ldots \\ +K(1.1025)^9(1.05)^2+K(1.1025)^{10}(1.05)^1 \\ =11 K(1.1025)^{11}+11 K(1.1025)^{11}(1.05) \\ =65.96463 K=11000 \end{gathered} [[/math]]


Thus [math]K=11000 / 65.96463=166.7560[/math].

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