Exercise
Nov 26'23
Answer
Solution: B
[[math]]
\begin{gathered}
\text { January } \quad \text { July } \\
K(1.05)^{22}+K(1.1025)(1.05)^{21} \\
+K(1.1025)(1.05)^{20}+K(1.1025)^2(1.05)^{19} \\
+\ldots+\ldots \\
+K(1.1025)^9(1.05)^2+K(1.1025)^{10}(1.05)^1 \\
=11 K(1.1025)^{11}+11 K(1.1025)^{11}(1.05) \\
=65.96463 K=11000
\end{gathered}
[[/math]]
Thus [math]K=11000 / 65.96463=166.7560[/math].