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| rev | Admin | (Created page with "'''Solution: A''' For fixed <math>y \in [0,1]</math>, we have <math>E[X^y] = \frac{1}{y+1}</math> and thus <math display = "block"> E[X^Y] = \int_{0}^1 \frac{1}{y+1} \, dy = \log(2). </math>") | Jun 28'24 at 3:03 | +193 |