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revprevAdminJan 18'24 at 2:34+23
revcurprevAdminJan 18'24 at 2:34+23
revcurprevAdminJan 18'24 at 2:33+23
revcurAdmin (Created page with "'''Answer: E''' <math display="block"> \begin{aligned} & e_{75: 10}=\int_{t=0}^{t=10}{ }_{t} p_{75} d t \quad \text { where }{ }_{t} p_{x}=\frac{{ }_{t+x} p_{0}}{{ }_{x} p_{0}}=\frac{1-\frac{(t+x)^{2}}{10000}}{1-\frac{x^{2}}{10000}}=\frac{10000-(t+x)^{2}}{10000-x^{2}} \text { for } 0< t <100-x \\ & =\int_{0}^{10} \frac{10000-75^{2}-150 t-t^{2}}{10000-75^{2}} d t \\ & =\frac{1}{4375} \cdot\left[4375 t-75 t^{2}-\frac{t^{3}}{3}\right]_{t=0}^{t=10}=8.21 \end{aligned} </math>")Jan 15'24 at 21:49+478