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| revprev | Admin | Jan 18'24 at 2:34 | +23 | ||
| revcurprev | Admin | Jan 18'24 at 2:34 | +23 | ||
| revcurprev | Admin | Jan 18'24 at 2:33 | +23 | ||
| revcur | Admin | (Created page with "'''Answer: C''' We need to determine <math>{ }_{3 \mid 2.5} q_{90}</math>. <math display="block"> { }_{3 \mid 2.5} q_{90}=\frac{l_{90+3}-l_{90+3+2.5}}{l_{90}}=\frac{l_{93}-l_{95.5}}{l_{90}}=\frac{l_{93}-\left(l_{95}-0.5 d_{95}\right)}{l_{90}}=\frac{825-[600-0.5(240)]}{1,000}=0.3450 </math> where <math>l_{90}=1,000, l_{93}=825, l_{97}=\frac{d_{97}}{q_{97}}=\frac{72}{1}=72, l_{96}=\frac{l_{97}}{p_{96}}=\frac{72}{0.2}=360</math>, <math>l_{95}=\frac{l_{96}}{p_{95}}=\f...") | Jan 16'24 at 2:28 | +553 |