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| rev | Admin | (Created page with "'''Solution: C''' The monthly interest rate is 0.042/12 = 0.0035. The quarterly interest rate is 1.0035<sup>3</sup>-1 = 0.0105. The investor makes 41 quarterly deposits and the ending date is 124 months from the start. Using January 1 of year y as the comparison date produces the following equation <math display = "block"> X+\sum_{k=1}^{41}{\frac{100}{1.0105^k}}={\frac{\textstyle1.9X}{\textstyle1.0035^{124}}} </math> {{soacopyright | 2023 }}") | Nov 18'23 at 10:31 | +450 |