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| revprev | Admin | Jan 18'24 at 1:34 | +23 | ||
| revcurprev | Admin | Jan 18'24 at 1:34 | +23 | ||
| revcurprev | Admin | Jan 18'24 at 1:33 | +23 | ||
| revcurprev | Admin | Jan 17'24 at 23:24 | +26 | m | |
| revcur | Admin | (Created page with "'''Answer: C''' <math display="block"> \begin{aligned} \mu_{x} & =-\frac{d}{d_{x}} \ln S_{0}(x)=-\frac{1}{3} \frac{d}{d_{x}} \ln \left(1-\frac{x}{60}\right) \\ & =\frac{1}{180}\left(1-\frac{x}{60}\right)^{-1}=\frac{1}{3(60-x)} \end{aligned} </math> Therefore, <math>1000 \mu_{35}=(1000) \frac{1}{3(25)}=\frac{1000}{75}=13.3</math>.") | Jan 15'24 at 19:34 | +336 |