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| rev | Admin | (Created page with "'''Solution: B''' Let <math>C</math> = Event that a policyholder buys collision coverage <math>D</math> = Event that a policyholder buys disability coverage Then we are given that <math>\operatorname{P}[C] = 2\operatorname{P}[D]</math> and <math>\operatorname{P}[C ∩ D] = 0.15</math>. By the independence of <math>C</math> and <math>D</math>, it therefore follows that <math display = "block"> 0.15 = \operatorname{P}[C ∩ D] = \operatorname{P}[C] \operatorname{P}[D]...") | Jul 1'24 at 9:45 | +1,076 |