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| revprev | Admin | Jun 13'24 at 1:05 | −15 | ||
| revcurprev | Admin | Jun 13'24 at 1:05 | −242 | ||
| revcur | Bot | (Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> \begin{sloppypar} Given that <math>P(X = a) = r</math>, <math>P(\max(X,Y) = a) = s</math>, and <math>P(\min(X,Y) = a) = t</math>, show that you can determine <math>u = P(Y = a)</math> in terms of <math>r</math>, <math>s</math>, and <math>t</math...") | Jun 9'24 at 3:17 | +486 |