exercise:Cc5799edfb: Difference between revisions

From Stochiki
(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> For correlated random variables <math>X</math> and <math>Y</math> it is natural to ask for the expected value for <math>X</math> given <math>Y</math>. For example, Galton calculated the expected value of the height of a son given the height of th...")
 
No edit summary
 
Line 1: Line 1:
<div class="d-none"><math>
For correlated random variables <math>X</math> and <math>Y</math> it is natural to ask for the expected value for <math>X</math> given <math>Y</math>.  For example, Galton calculated the
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div> For correlated random variables <math>X</math> and <math>Y</math> it is natural to
ask for the expected value for <math>X</math> given <math>Y</math>.  For example, Galton calculated the
expected value of the height of a son given the height of the father.  He used this
expected value of the height of a son given the height of the father.  He used this
to show that tall men can be expected to have sons who are less tall on the average.  
to show that tall men can be expected to have sons who are less tall on the average.  
Line 22: Line 15:
E(X|Y = y) = \int_a^b x f_{X|Y}(x|y)\, dx\ .
E(X|Y = y) = \int_a^b x f_{X|Y}(x|y)\, dx\ .
</math>
</math>
For the normal density in Exercise [[exercise:Bf1fbb9234 |Exercise]], show that the conditional
For the normal density in [[exercise:Bf1fbb9234 |Exercise]], show that the conditional
density of <math>f_{X|Y}(x|y)</math> is normal with mean <math>\rho y</math> and variance <math>1 - \rho^2</math>.  
density of <math>f_{X|Y}(x|y)</math> is normal with mean <math>\rho y</math> and variance <math>1 - \rho^2</math>.  
From this we see that if <math>X</math> and <math>Y</math> are positively correlated <math>(0  <  \rho  <  1)</math>,
From this we see that if <math>X</math> and <math>Y</math> are positively correlated <math>(0  <  \rho  <  1)</math>,
and if <math>y  >  E(Y)</math>, then the expected value for <math>X</math> given <math>Y = y</math> will be less than <math>y</math>
and if <math>y  >  E(Y)</math>, then the expected value for <math>X</math> given <math>Y = y</math> will be less than <math>y</math>
(i.e., we have regression on the mean).
(i.e., we have regression on the mean).

Latest revision as of 22:47, 14 June 2024

For correlated random variables [math]X[/math] and [math]Y[/math] it is natural to ask for the expected value for [math]X[/math] given [math]Y[/math]. For example, Galton calculated the expected value of the height of a son given the height of the father. He used this to show that tall men can be expected to have sons who are less tall on the average. Similarly, students who do very well on one exam can be expected to do less well on the next exam, and so forth. This is called regression on the mean. To define this conditional expected value, we first define a conditional density of [math]X[/math] given [math]Y = y[/math] by

[[math]] f_{X|Y}(x|y) = \frac {f_{X,Y}(x,y)}{f_Y(y)}\ , [[/math]]

where [math]f_{X,Y}(x,y)[/math] is the joint density of [math]X[/math] and [math]Y[/math], and [math]f_Y[/math] is the density for [math]Y[/math]. Then the conditional expected value of [math]X[/math] given [math]Y[/math] is

[[math]] E(X|Y = y) = \int_a^b x f_{X|Y}(x|y)\, dx\ . [[/math]]

For the normal density in Exercise, show that the conditional density of [math]f_{X|Y}(x|y)[/math] is normal with mean [math]\rho y[/math] and variance [math]1 - \rho^2[/math]. From this we see that if [math]X[/math] and [math]Y[/math] are positively correlated [math](0 \lt \rho \lt 1)[/math], and if [math]y \gt E(Y)[/math], then the expected value for [math]X[/math] given [math]Y = y[/math] will be less than [math]y[/math] (i.e., we have regression on the mean).