excans:9938b2eea6: Difference between revisions
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(Created page with "'''Answer: B''' <math display="block"> \begin{aligned} & e_{40}=e_{40: 20}+{ }_{20} p_{40} \cdot e_{60} \\ & =18+(1-0.2)(25) \\ & =38 \\ & e_{40}=e_{40: 11}+p_{40} \cdot e_{41} \\ & \Rightarrow e_{41}=\frac{e_{40}-e_{40: 11}}{p_{40}}=\frac{e_{40}-p_{40}}{p_{40}}=\frac{38-0.997}{0.997}=37.11434 \end{aligned} </math>") |
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Latest revision as of 02:34, 18 January 2024
Answer: B
[[math]]
\begin{aligned}
& e_{40}=e_{40: 20}+{ }_{20} p_{40} \cdot e_{60} \\
& =18+(1-0.2)(25) \\
& =38 \\
& e_{40}=e_{40: 11}+p_{40} \cdot e_{41} \\
& \Rightarrow e_{41}=\frac{e_{40}-e_{40: 11}}{p_{40}}=\frac{e_{40}-p_{40}}{p_{40}}=\frac{38-0.997}{0.997}=37.11434
\end{aligned}
[[/math]]
Copyright 2024 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.