exercise:2f6a78a924: Difference between revisions
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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> For examples such as those in Exercises Exercise and Exercise, it might seem that at least you should not have to wait on average ''more'' than 10 minutes if the average time between occurrences i...") |
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\newcommand{\mathds}{\mathbb}</math></div> For examples such as those in Exercises [[exercise:8b408c8df0 |Exercise]] and | \newcommand{\mathds}{\mathbb}</math></div> For examples such as those in Exercises [[exercise:8b408c8df0 |Exercise]] and [[exercise:B52419720c |Exercise]], it might seem that at least you should not have to wait on average ''more'' | ||
[[exercise:B52419720c |Exercise]], it might seem that at least you should not have to wait on average ''more'' | |||
than 10 minutes if the average time between occurrences is 10 minutes. Alas, even this is not | than 10 minutes if the average time between occurrences is 10 minutes. Alas, even this is not | ||
true. To see why, consider the following assumption | true. To see why, consider the following assumption | ||
Revision as of 22:40, 12 June 2024
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For examples such as those in Exercises Exercise and Exercise, it might seem that at least you should not have to wait on average more
than 10 minutes if the average time between occurrences is 10 minutes. Alas, even this is not true. To see why, consider the following assumption about the times between occurrences. Assume that the time between occurrences is 3 minutes with probability .9 and 73 minutes with probability .1. Show by simulation that the average time between occurrences is 10 minutes, but that if you come upon this system at time 100, your average waiting time is more than 10 minutes.