exercise:A4584be380: Difference between revisions
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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> Prove that if <math>A</math> and <math>B</math> are independent so are <ul><li> <math>A</math> and <math>\tilde B</math>. </li> <li> <math>\tilde A</math> and <math>\tilde B</math>. </li> </ul>") |
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\newcommand{\NA}{{\rm NA}} | \newcommand{\NA}{{\rm NA}} | ||
\newcommand{\mathds}{\mathbb}</math></div> Prove that if <math>A</math> and <math>B</math> are independent so are | \newcommand{\mathds}{\mathbb}</math></div> Prove that if <math>A</math> and <math>B</math> are independent so are | ||
<ul><li> <math>A</math> and <math>\tilde B</math>. | <ul style="list-style-type:lower-alpha"><li> <math>A</math> and <math>\tilde B</math>. | ||
</li> | </li> | ||
<li> <math>\tilde A</math> and <math>\tilde B</math>. | <li> <math>\tilde A</math> and <math>\tilde B</math>. | ||
</li> | </li> | ||
</ul> | </ul> | ||
Latest revision as of 00:45, 13 June 2024
[math]
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}[/math]
Prove that if [math]A[/math] and [math]B[/math] are independent so are
- [math]A[/math] and [math]\tilde B[/math].
- [math]\tilde A[/math] and [math]\tilde B[/math].