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(Created page with "'''Answer: E''' The distribution is binomial with 10,000 trials. <math display="block"> \begin{aligned} & \operatorname{Var}\left[L_{15}\right]=n p q=10,000\left({ }_{15} p_{50}\right)\left({ }_{15} q_{50}\right) \\ & { }_{15} p_{50}=e^{\left[-A(15)-\frac{B}{\ln C} c^{50}\left(c^{15}-1\right)\right]}=0.837445 \\ & { }_{15} q_{50}=1-{ }_{15} p_{50}=0.162555 \end{aligned} </math> <math>\operatorname{Var}\left[L_{15}\right]=10,000(0.837445)(0.162555)=1361.3</math>") |
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<math>\operatorname{Var}\left[L_{15}\right]=10,000(0.837445)(0.162555)=1361.3</math> | <math>\operatorname{Var}\left[L_{15}\right]=10,000(0.837445)(0.162555)=1361.3</math> | ||
{{soacopyright | 2024 }} | |||
Revision as of 00:29, 18 January 2024
Answer: E
The distribution is binomial with 10,000 trials.
[[math]]
\begin{aligned}
& \operatorname{Var}\left[L_{15}\right]=n p q=10,000\left({ }_{15} p_{50}\right)\left({ }_{15} q_{50}\right) \\
& { }_{15} p_{50}=e^{\left[-A(15)-\frac{B}{\ln C} c^{50}\left(c^{15}-1\right)\right]}=0.837445 \\
& { }_{15} q_{50}=1-{ }_{15} p_{50}=0.162555
\end{aligned}
[[/math]]
[math]\operatorname{Var}\left[L_{15}\right]=10,000(0.837445)(0.162555)=1361.3[/math]
Copyright 2024 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.