exercise:42db0d031a: Difference between revisions

From Stochiki
(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> <ul><li> Suppose that you are looking in your desk for a letter from some time ago. Your desk has eight drawers, and you assess the probability that it is in any particular drawer is 10\% (so there is a 20\% chance that it is not in the desk at...")
 
No edit summary
Line 6: Line 6:
\newcommand{\NA}{{\rm NA}}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div>  
\newcommand{\mathds}{\mathbb}</math></div>  
<ul><li>
<ul style="list-style-type:lower-alpha"><li>
Suppose that you are looking in your desk for a letter from some time ago.  Your desk has eight
Suppose that you are looking in your desk for a letter from some time ago.  Your desk has eight
drawers, and you assess the probability that it is in any particular drawer is 10\% (so there is
drawers, and you assess the probability that it is in any particular drawer is 10% (so there is
a 20\% chance that it is not in the desk at all).  Suppose now that you start searching  
a 20% chance that it is not in the desk at all).  Suppose now that you start searching  
systematically through your desk, one drawer at a time.  In addition, suppose that you have not found
systematically through your desk, one drawer at a time.  In addition, suppose that you have not found
the letter in the first <math>i</math> drawers, where <math>0 \le i \le 7</math>.  Let <math>p_i</math> denote the probability that
the letter in the first <math>i</math> drawers, where <math>0 \le i \le 7</math>.  Let <math>p_i</math> denote the probability that
Line 15: Line 15:
will be found in some subsequent drawer (both <math>p_i</math> and <math>q_i</math> are conditional probabilities, since
will be found in some subsequent drawer (both <math>p_i</math> and <math>q_i</math> are conditional probabilities, since
they are based upon the assumption that the letter is not in the first <math>i</math> drawers).  Show that
they are based upon the assumption that the letter is not in the first <math>i</math> drawers).  Show that
the <math>p_i</math>'s increase and the <math>q_i</math>'s decrease.  (This problem is from Falk et al.<ref group="Notes" >R.\
the <math>p_i</math>'s increase and the <math>q_i</math>'s decrease.  (This problem is from Falk et al.<ref group="Notes" >R.
Falk, A.\ Lipson, and C.\ Konold, “The ups and downs of the hope function in a fruitless search,”
Falk, A. Lipson, and C. Konold, “The ups and downs of the hope function in a fruitless search,”
in ''Subjective Probability,'' G.\ Wright and P.\ Ayton, (eds.) (Chichester: Wiley, 1994), pgs.
in ''Subjective Probability,'' G.\ Wright and P.\ Ayton, (eds.) (Chichester: Wiley, 1994), pgs.
353-377.</ref>)
353-377.</ref>)
Line 24: Line 24:
numbers:  Alarming disease data are frequently flawed,” ''Wall Street Journal,'' 11 April 1996, p.
numbers:  Alarming disease data are frequently flawed,” ''Wall Street Journal,'' 11 April 1996, p.
B1.</ref> For the ages 20, 30, 40, 50, and 60, the probability of a  
B1.</ref> For the ages 20, 30, 40, 50, and 60, the probability of a  
woman in the U.S.\ developing cancer in the next ten years is 0.5\%, 1.2\%, 3.2\%, 6.4\%, and 10.8\%,
woman in the U.S.\ developing cancer in the next ten years is 0.5%, 1.2%, 3.2%, 6.4%, and 10.8%,
respectively.  At the same set of ages, the probability of a woman in the U.S.\ eventually developing cancer is
respectively.  At the same set of ages, the probability of a woman in the U.S.\ eventually developing cancer is
39.6\%, 39.5\%, 39.1\%, 37.5\%, and 34.2\%, respectively.  Do you think that the problem in part (a) gives an
39.6%, 39.5%, 39.1%, 37.5%, and 34.2%, respectively.  Do you think that the problem in part (a) gives an
explanation for these data?  
explanation for these data?  
</li>
</li>

Revision as of 00:21, 13 June 2024

[math] \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}[/math]
  • Suppose that you are looking in your desk for a letter from some time ago. Your desk has eight drawers, and you assess the probability that it is in any particular drawer is 10% (so there is a 20% chance that it is not in the desk at all). Suppose now that you start searching systematically through your desk, one drawer at a time. In addition, suppose that you have not found the letter in the first [math]i[/math] drawers, where [math]0 \le i \le 7[/math]. Let [math]p_i[/math] denote the probability that the letter will be found in the next drawer, and let [math]q_i[/math] denote the probability that the letter will be found in some subsequent drawer (both [math]p_i[/math] and [math]q_i[/math] are conditional probabilities, since they are based upon the assumption that the letter is not in the first [math]i[/math] drawers). Show that the [math]p_i[/math]'s increase and the [math]q_i[/math]'s decrease. (This problem is from Falk et al.[Notes 1])
  • The following data appeared in an article in the Wall Street Journal.[Notes 2] For the ages 20, 30, 40, 50, and 60, the probability of a woman in the U.S.\ developing cancer in the next ten years is 0.5%, 1.2%, 3.2%, 6.4%, and 10.8%, respectively. At the same set of ages, the probability of a woman in the U.S.\ eventually developing cancer is 39.6%, 39.5%, 39.1%, 37.5%, and 34.2%, respectively. Do you think that the problem in part (a) gives an explanation for these data?

Notes

  1. R. Falk, A. Lipson, and C. Konold, “The ups and downs of the hope function in a fruitless search,” in Subjective Probability, G.\ Wright and P.\ Ayton, (eds.) (Chichester: Wiley, 1994), pgs. 353-377.
  2. C. Crossen, “Fright by the numbers: Alarming disease data are frequently flawed,” Wall Street Journal, 11 April 1996, p. B1.