excans:5fda483341: Difference between revisions
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(Created page with "'''Answer: B''' <math display="block"> \begin{aligned} & { }_{20} q_{30}=\frac{S_{0}(30)-S_{0}(50)}{S_{0}(30)}=\frac{\left(1-\frac{30}{250}\right)-\left(1-\left[\frac{50}{100}\right]^{2}\right)}{1-\frac{30}{250}}=\frac{\frac{220}{250}-\frac{3}{4}}{\frac{220}{250}} \\ & =\frac{440-375}{440}=\frac{65}{440}=\frac{13}{88}=0.1477 \end{aligned} </math>") |
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Revision as of 00:25, 18 January 2024
Answer: B
[[math]]
\begin{aligned}
& { }_{20} q_{30}=\frac{S_{0}(30)-S_{0}(50)}{S_{0}(30)}=\frac{\left(1-\frac{30}{250}\right)-\left(1-\left[\frac{50}{100}\right]^{2}\right)}{1-\frac{30}{250}}=\frac{\frac{220}{250}-\frac{3}{4}}{\frac{220}{250}} \\
& =\frac{440-375}{440}=\frac{65}{440}=\frac{13}{88}=0.1477
\end{aligned}
[[/math]]
Copyright 2024 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.