excans:380cee40f6: Difference between revisions

Revision as of 02:34, 18 January 2024

Answer: D

[math]\hat{S}(21.0)=\frac{59}{60} \times \frac{59-8+1-1}{59-8+1} \times \frac{51-6+7-2}{51-6+7} \times \frac{50-7+7-1}{50-7+7} \times \frac{49-6+5-1}{49-6+5}=0.8899[/math]

[math]\operatorname{Var}[\hat{S}(21.0)] \approx 0.8899^{2}\left(\frac{1}{60 \times 59}+\frac{1}{52 \times 51}+\frac{2}{52 \times 50}+\frac{1}{50 \times 49}+\frac{1}{48 \times 47}\right)=0.00181[/math]

The upper limit of the [math]80 \%[/math] linear confidence interval is

[[math]] 0.8899+1.282(0.00181)^{0.5}=0.944 [[/math]]

@@ Line 11: / Line 11: @@
 .8899+1.282(0.00181)^{0.5}=0.944
 </math>
+{{soacopyright|2024}}
 {{soacopyright|2024}}
 {{soacopyright|2024}}