Revision as of 00:25, 18 January 2024 by Admin

Exercise


ABy Admin
Jan 15'24

Answer

Answer: B

[[math]] \begin{aligned} & { }_{20} q_{30}=\frac{S_{0}(30)-S_{0}(50)}{S_{0}(30)}=\frac{\left(1-\frac{30}{250}\right)-\left(1-\left[\frac{50}{100}\right]^{2}\right)}{1-\frac{30}{250}}=\frac{\frac{220}{250}-\frac{3}{4}}{\frac{220}{250}} \\ & =\frac{440-375}{440}=\frac{65}{440}=\frac{13}{88}=0.1477 \end{aligned} [[/math]]

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