Revision as of 01:59, 16 January 2024 by Admin (Created page with "'''Answer: B''' <math display="block"> \begin{aligned} { }_{2.5} q_{[50]+0.4} & =1-{ }_{2.5} p_{[50]+0.4}=1-{ }_{2.9} p_{[50]} /\left(p_{[50]}\right)^{0.4} \\ & =1-\left\{p_{[50]} p_{[50]+1}\left(p_{52}\right)^{0.9}\right\} /\left(1-q_{[50]}\right)^{0.4} \\ & =1-\left\{\left(1-q_{[50]}\right)\left(1-q_{[50]+1}\right)\left(1-q_{52}\right)^{0.9}\right\} /\left(1-q_{[50]}\right)^{0.4} \\ & =1-\left\{(1-0.0050)(1-0.0063)(1-0.0080)^{0.9}\right\} /(1-0.0050)^{0.4} \\ & =0.01...")
Exercise
Jan 16'24
Answer
Answer: B
[[math]]
\begin{aligned}
{ }_{2.5} q_{[50]+0.4} & =1-{ }_{2.5} p_{[50]+0.4}=1-{ }_{2.9} p_{[50]} /\left(p_{[50]}\right)^{0.4} \\
& =1-\left\{p_{[50]} p_{[50]+1}\left(p_{52}\right)^{0.9}\right\} /\left(1-q_{[50]}\right)^{0.4} \\
& =1-\left\{\left(1-q_{[50]}\right)\left(1-q_{[50]+1}\right)\left(1-q_{52}\right)^{0.9}\right\} /\left(1-q_{[50]}\right)^{0.4} \\
& =1-\left\{(1-0.0050)(1-0.0063)(1-0.0080)^{0.9}\right\} /(1-0.0050)^{0.4} \\
& =0.01642
\end{aligned}
[[/math]]
[math]1000_{2.5} q_{[50]+0.4}=16.42[/math]