Revision as of 01:07, 26 June 2024 by Admin (Created page with "'''Solution: A''' The number of ways choosing 5 items with exactly one defective item equals <math display = "block">5 \binom{15}{4}</math> out of a total of <math>\binom{20}{5}</math> ways of choosing 5 items. Hence the probability equals <math display = "block"> \frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402. </math>")
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Exercise


ABy Admin
Jun 26'24

Answer

Solution: A

The number of ways choosing 5 items with exactly one defective item equals

[[math]]5 \binom{15}{4}[[/math]]

out of a total of [math]\binom{20}{5}[/math] ways of choosing 5 items. Hence the probability equals

[[math]] \frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402. [[/math]]

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