Revision as of 01:07, 26 June 2024 by Admin (Created page with "'''Solution: A''' The number of ways choosing 5 items with exactly one defective item equals <math display = "block">5 \binom{15}{4}</math> out of a total of <math>\binom{20}{5}</math> ways of choosing 5 items. Hence the probability equals <math display = "block"> \frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402. </math>")
Exercise
ABy Admin
Jun 26'24
Answer
Solution: A
The number of ways choosing 5 items with exactly one defective item equals
[[math]]5 \binom{15}{4}[[/math]]
out of a total of [math]\binom{20}{5}[/math] ways of choosing 5 items. Hence the probability equals
[[math]]
\frac{5 \binom{15}{4}}{\binom{20}{5}} = 0.4402.
[[/math]]