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Exercise
Apr 29'23
Answer
Solution: C
Let R be the event the car is red and G be the event the car is green. Let E be the event that the claim exceeds the deductible. Then,
[[math]]
\operatorname{P}(R | E ) = \frac{\operatorname{P}( R) \operatorname{P}( E | R)}{\operatorname{P}( R ) \operatorname{P}( E | R ) + \operatorname{P}(G) \operatorname{P}( E | G)} = \frac{0.3(0.09)}{0.3(0.09) + 0.7(0.04)} = \frac{0.027}{0.055} = 0.491.
[[/math]]
Note that if A is the probability of an accident,
[[math]]
\operatorname{P}( E | R ) = \operatorname{P}( E | R \cap A) \operatorname{P}( A | R ) = 0.1(0.9) = 0.09.
[[/math]]