Exercise


Apr 29'23

Answer

Solution: C

Let R be the event the car is red and G be the event the car is green. Let E be the event that the claim exceeds the deductible. Then,

[[math]] \operatorname{P}(R | E ) = \frac{\operatorname{P}( R) \operatorname{P}( E | R)}{\operatorname{P}( R ) \operatorname{P}( E | R ) + \operatorname{P}(G) \operatorname{P}( E | G)} = \frac{0.3(0.09)}{0.3(0.09) + 0.7(0.04)} = \frac{0.027}{0.055} = 0.491. [[/math]]

Note that if A is the probability of an accident,

[[math]] \operatorname{P}( E | R ) = \operatorname{P}( E | R \cap A) \operatorname{P}( A | R ) = 0.1(0.9) = 0.09. [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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