Revision as of 20:14, 7 May 2023 by Admin (Created page with "'''Solution: C''' <math display = "block"> \begin{align*} E[100(0.5)^X] = 100 E[(0.5)^X] = 100E[e^{(\ln(0.5)}X] &= 100M_X(\ln(0.5))\\ &= 100 \frac{1}{1-2\ln(0.5)}\\ &= 41.9....")
Exercise
May 07'23
Answer
Solution: C
[[math]]
\begin{align*}
E[100(0.5)^X] = 100 E[(0.5)^X] = 100E[e^{(\ln(0.5)}X] &= 100M_X(\ln(0.5))\\ &= 100 \frac{1}{1-2\ln(0.5)}\\ &= 41.9.
\end{align*}
[[/math]]