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Exercise
May 08'23
Answer
Solution: B
The requested probability can be determined as P(3 of first 11 damaged) P(12th is damaged | 3 of first 11 damaged)
[[math]]
= \frac{\binom{7}{3} \binom{13}{8}}{\frac{20}{11}} \frac{4}{9} = \frac{351(1287)}{167960} \frac{4}{9} = 0.119.
[[/math]]
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