Revision as of 23:36, 18 November 2023 by Admin (Created page with "'''Solution: C''' <math display = "block"> \begin{array}{l}{{1- v^{2}=0.52{\bar{s}}(1- v^{4})\Rightarrow1=0.52{\bar{s}}(1+ v^{2})\Rightarrow v^{2}=0.90476\Rightarrow v=0.95119}}\\ {{1- v^{2}=0.1427(1- v^{n})\Rightarrow1- v^n=(1-0.90476)/0.1427=0.667414\Rightarrow v^{n}=0.3325966}}\\ {{n=\ln(0.32596)/\ln(0.95119)=22}}\end{array} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: C
[[math]]
\begin{array}{l}{{1- v^{2}=0.52{\bar{s}}(1- v^{4})\Rightarrow1=0.52{\bar{s}}(1+ v^{2})\Rightarrow v^{2}=0.90476\Rightarrow v=0.95119}}\\ {{1- v^{2}=0.1427(1- v^{n})\Rightarrow1- v^n=(1-0.90476)/0.1427=0.667414\Rightarrow v^{n}=0.3325966}}\\ {{n=\ln(0.32596)/\ln(0.95119)=22}}\end{array}
[[/math]]
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.