Exercise
ABy Admin
Nov 18'23
Answer
Solution: C
[[math]]
\begin{array}{l}{{1- v^{2}=0.52{\bar{s}}(1- v^{4})\Rightarrow1=0.52{\bar{s}}(1+ v^{2})\Rightarrow v^{2}=0.90476\Rightarrow v=0.95119}}\\ {{1- v^{2}=0.1427(1- v^{n})\Rightarrow1- v^n=(1-0.90476)/0.1427=0.667414\Rightarrow v^{n}=0.3325966}}\\ {{n=\ln(0.32596)/\ln(0.95119)=22}}\end{array}
[[/math]]