Revision as of 18:27, 19 November 2023 by Admin (Created page with "'''Solution: A''' <math display = "block"> \begin{align*} 1050.50=(22.50+X)a_{\overline{14}|0.03}+ X\left({\frac{a_{\overline{14}|0.03}-14(1.03)^{-14}}{0.03}}\right) +300(1.03)^{-14} \\ 1050.50=(22.50+X)11.2961+X\left({\frac{11.2961-9.25565}{0.03}}\right)+198.335 \implies 79.3111X \implies 598=7.54 \end{align*} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 19'23
Answer
Solution: A
[[math]]
\begin{align*}
1050.50=(22.50+X)a_{\overline{14}|0.03}+ X\left({\frac{a_{\overline{14}|0.03}-14(1.03)^{-14}}{0.03}}\right)
+300(1.03)^{-14} \\
1050.50=(22.50+X)11.2961+X\left({\frac{11.2961-9.25565}{0.03}}\right)+198.335 \implies 79.3111X \implies 598=7.54
\end{align*}
[[/math]]
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.