Exercise


ABy Admin
Nov 19'23

Answer

Solution: A

[[math]] \begin{align*} 1050.50=(22.50+X)a_{\overline{14}|0.03}+ X\left({\frac{a_{\overline{14}|0.03}-14(1.03)^{-14}}{0.03}}\right) +300(1.03)^{-14} \\ 1050.50=(22.50+X)11.2961+X\left({\frac{11.2961-9.25565}{0.03}}\right)+198.335 \implies 79.3111X \implies 598=7.54 \end{align*} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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