Revision as of 11:51, 20 November 2023 by Admin (Created page with "'''Solution: E''' <math display = "block"> \begin{array}{l}{{(1+s_{3})^{3}=(1+s_{2})^{2}(1+1f_{2})}}\\ {{0.85892={\frac{1}{(1+s_{2})^{3}}},s_{3}=0.052}}\\ {{0.90703=\frac{1}{(1+s_{2})^{2}},s_{2}=0.050 }}\\ {{1.052^{3}=1.050^{2}(1+_1f_{2}) }}\\ {{_1f_{2} = 0.056}}\end{array} </math> {{soacopyright | 2023 }}")
Exercise
Nov 20'23
Answer
Solution: E
[[math]]
\begin{array}{l}{{(1+s_{3})^{3}=(1+s_{2})^{2}(1+1f_{2})}}\\ {{0.85892={\frac{1}{(1+s_{2})^{3}}},s_{3}=0.052}}\\ {{0.90703=\frac{1}{(1+s_{2})^{2}},s_{2}=0.050
}}\\ {{1.052^{3}=1.050^{2}(1+_1f_{2})
}}\\ {{_1f_{2} = 0.056}}\end{array}
[[/math]]
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