Revision as of 12:47, 20 November 2023 by Admin (Created page with "'''Solution: B''' <math display = "block">P(0.1025)\approx P(0.10){\Biggl({\frac{1.10}{1.1025}}{\Biggr)}}^{11}=0.97534P(0.10). </math> Therefore, the approximate percentage price change is 100(0.97534 – 1) = –2.47%. {{soacopyright | 2023 }}")
Exercise
Nov 20'23
Answer
Solution: B
[[math]]P(0.1025)\approx P(0.10){\Biggl({\frac{1.10}{1.1025}}{\Biggr)}}^{11}=0.97534P(0.10).
[[/math]]
Therefore, the approximate percentage price change is 100(0.97534 – 1) = –2.47%.
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