Exercise


Nov 20'23

Answer

Solution: B

[[math]]P(0.1025)\approx P(0.10){\Biggl({\frac{1.10}{1.1025}}{\Biggr)}}^{11}=0.97534P(0.10). [[/math]]

Therefore, the approximate percentage price change is 100(0.97534 – 1) = –2.47%.

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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