Revision as of 19:53, 20 November 2023 by Admin (Created page with "'''Solution: D''' Set up the following two equations in the two unknowns: <math display = "block"> \begin{array}{cc}{{A(1.05)^{2}+B(1.05)^{-2}=6000}}\\ {{2A(1.05)^{1}-2B(1.05)^{-3}=0.}}\end{array} </math> Solving simultaneously gives: <math display = "block"> \begin{array}{l}{{A=2721.09}}\\ {{B=3307.50}}\\ {{|A-B|=586.41}}\end{array} </math> {{soacopyright | 2023 }}")
Exercise
Nov 20'23
Answer
Solution: D
Set up the following two equations in the two unknowns:
[[math]]
\begin{array}{cc}{{A(1.05)^{2}+B(1.05)^{-2}=6000}}\\ {{2A(1.05)^{1}-2B(1.05)^{-3}=0.}}\end{array}
[[/math]]
Solving simultaneously gives:
[[math]]
\begin{array}{l}{{A=2721.09}}\\ {{B=3307.50}}\\ {{|A-B|=586.41}}\end{array}
[[/math]]
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.