Exercise


Nov 20'23

Answer

Solution: D

Set up the following two equations in the two unknowns:

[[math]] \begin{array}{cc}{{A(1.05)^{2}+B(1.05)^{-2}=6000}}\\ {{2A(1.05)^{1}-2B(1.05)^{-3}=0.}}\end{array} [[/math]]

Solving simultaneously gives:

[[math]] \begin{array}{l}{{A=2721.09}}\\ {{B=3307.50}}\\ {{|A-B|=586.41}}\end{array} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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