Revision as of 16:55, 29 November 2023 by Admin (Created page with "'''Solution: C''' <math>1014(1+j)^{20}=1000+.04 * 1000 * s_{\overline{40} \mid .03}</math> so <math display = "block">j=\left(\frac{1000+40 s_{\overline{40} \mid .03}}{1014}\right)^{1 / 20}-1=.071243</math> '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}")
Exercise
Nov 29'23
Answer
Solution: C
[math]1014(1+j)^{20}=1000+.04 * 1000 * s_{\overline{40} \mid .03}[/math] so
[[math]]j=\left(\frac{1000+40 s_{\overline{40} \mid .03}}{1014}\right)^{1 / 20}-1=.071243[[/math]]
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.