Exercise


Nov 29'23

Answer

Solution: C

[math]1014(1+j)^{20}=1000+.04 * 1000 * s_{\overline{40} \mid .03}[/math] so

[[math]]j=\left(\frac{1000+40 s_{\overline{40} \mid .03}}{1014}\right)^{1 / 20}-1=.071243[[/math]]

References

Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.

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