Revision as of 02:34, 18 January 2024 by Admin
Exercise
Jan 16'24
Answer
Answer: B
[math]E(N)=1000\left({ }_{40} p_{35}+{ }_{40} p_{45}\right)=1000\left(\frac{85,203.5}{99,556.7}+\frac{61,184.9}{99,033.9}\right)=1473.65[/math]
[math]\operatorname{Var}(N)=1000_{40} p_{35}\left(1-{ }_{40} p_{35}\right)+1000_{40} p_{45}\left(1-{ }_{40} p_{45}\right)=359.50[/math]
Since [math]1473.65+1.645 \sqrt{359.50}=1504.84[/math]
[math]N=1505[/math]