Revision as of 21:13, 13 May 2024 by Admin (Created page with "One possible solution: <syntaxhighlight lang="C"> #include<stdio.h> // This is the fastest way int main(void) { int n; scanf("%d",&n); for(int i=0;i<n;i++) { for(int j=0;j<=i;j++) putchar(42); putchar(10); } for(int i=n-1;i>0;i--) { for(int j=0;j<i;j++) putchar(42); putchar(10); } while((n=getchar())!=10); getchar(); return 0; } </syntaxhighlight> or like this (all math) <syntaxhighlight lang="C"> void sideways(int n) {...")
Exercise
May 13'24
Answer
One possible solution:
#include
int n; scanf("%d",&n); for(int i=0;i
0;i--) { for(int j=0;j
}
or like this (all math)
void sideways(int n) {
int i=0,j=0; for(i=1;i<2*n;i++){ for(j=1;j<=(n-(abs(n-i)));j++){printf("*"); } printf("\n");
}
}