Exercise
May 13'24
Answer
One possible solution:
#include
int n; scanf("%d",&n); for(int i=0;i
0;i--) { for(int j=0;j
}
or like this (all math)
void sideways(int n) {
int i=0,j=0; for(i=1;i<2*n;i++){ for(j=1;j<=(n-(abs(n-i)));j++){printf("*"); } printf("\n");
}
}