Exercise
Apr 30'23
Answer
Solution: D
Let
[math]O[/math] = Event of operating room charges
[math]E[/math] = Event of emergency room charges
Then
[[math]]
0.85 = \operatorname{P}( O ∪ E ) = \operatorname{P}( O ) + \operatorname{P}( E ) − \operatorname{P}( O ∩ E ) = \operatorname{P}( O ) + \operatorname{P}( E ) − \operatorname{P}( O ) \operatorname{P}( E ).
[[/math]]
Since [math]\operatorname{P}( E^c ) = 0.25 = 1 − \operatorname{P}( E )[/math] , it follows [math]\operatorname{P}( E ) = 0.75 . [/math]
So
[[math]]
\begin{align*}
0.85 &= \operatorname{P}( O ) + 0.75 − \operatorname{P}( O )( 0.75 ) \\
\operatorname{P}( O )(1 − 0.75 ) &= 0.10 \\
\operatorname{P}( O ) &= 0.40
\end{align*}
[[/math]]