Exercise


ABy Admin
Nov 17'23

Answer

Solution: B

[[math]] \begin{aligned} & e^{\int_0^{20} \frac{2}{1+2 t} d t}=e^{\left.\ln (1+2 t)\right|_0 ^{20}}=41 \\ & 41=(1+i)^{20} \\ & i=0.204035 \\ & (1+0.204035)^5=2.53\end{aligned} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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