Exercise
ABy Admin
May 13'23
Answer
Key: B
For the severity distribution the mean is 5,000 and the variance is 10,0002 /12 . For credibility based on accuracy with regard to the number of claims,
[[math]]
2000 = \left (\frac{z}{0.03} \right)^2, z^2 = 1.8
[[/math]]
Where z is the appropriate value from the standard normal distribution. For credibility based on accuracy with regard to the total cost of claims, the number of claims needed is
[[math]]
\frac{z^2}{0.05^2} \left( 1 + \frac{1000^2/12}{5000^2}\right) = 960.
[[/math]]