Exercise
ABy Admin
Nov 18'23
Answer
Solution: C
[[math]]
\begin{array}{l}{{20.000=X\left(a_{\overline{5}|0.11}+1.11^{-5}a_{\overline{5}|0.12}\right)=X(3.69590+3.60478/1.68506)=5.83516\,X}}\\ {{\mathrm{X=20.000}/5.83516=3427.50.}}
\end{array}
[[/math]]