Exercise
ABy Admin
Nov 19'23
Answer
[[math]]
\begin{aligned} & 1.12=\left[1+\frac{i^{(12)}}{12}\right]^{12} \\ & \frac{i^{(12)}}{12}=0.00948879 \\ & 900=P\left(\frac{1}{1.00948879}\right)^{60-3+1} \\ & P=1556.43 \\ & P_{33}=1556.43\left(\frac{1}{1.00948879}\right)^{60-33+1}=1194.78\end{aligned}
[[/math]]