Exercise
ABy Admin
Nov 19'23
Answer
Solution: A
For the first bond:
[[math]]
(0.076)(6000)a_{\overline{20}|0.065}+6000v^{20}, \, P = 6727.22.
[[/math]]
For the second bond:
[[math]]
6727.22=(r)(7500)a_{\overline{{{20}}}\mid0.065}+7500v^{20}, \, 7500r = 417.37, \implies r = 0.0556.
[[/math]]