Exercise


ABy Admin
Apr 29'23

Answer

Solution: D

Let B, C, and D be the events of an accident occurring in 2014, 2013, and 2012, respectively. Let A = B ∪ C ∪ D .

[[math]] \operatorname{P}[B | A] = \frac{P[ A | B]P[ B]}{P[ A | B][ P[ B] + P[ A | C ]P[C ] + P[ A | D]P[ D]} [[/math]]

Use Bayes’ Theorem

[[math]] \frac{(0.05)(0.16)}{(0.05)(0.16) + (0.02)(0.18) + (0.03)(0.20)} = 0.45. [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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