Exercise


Nov 20'23

Answer

Solution: A

[[math]] 121,212=123,000\bigg(\frac{1.05}{1.054}\bigg)^{D_{MAC}}\Rightarrow D_{MAC}=\frac{\ln(121,212/123,000)}{\ln(1.05/1.054)}=3.851 [[/math]]

Then [math]D_{MOD} = 3.8512 /1.05 = 3.67[/math]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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